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25x^2-70x-33=0
a = 25; b = -70; c = -33;
Δ = b2-4ac
Δ = -702-4·25·(-33)
Δ = 8200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8200}=\sqrt{100*82}=\sqrt{100}*\sqrt{82}=10\sqrt{82}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-10\sqrt{82}}{2*25}=\frac{70-10\sqrt{82}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+10\sqrt{82}}{2*25}=\frac{70+10\sqrt{82}}{50} $
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